Question

va rog rezolvati calculul

Answer 1

$\it \dfrac{^{3+2\sqrt2)}1}{\ \ 3-2\sqrt2}-\dfrac{^{3-2\sqrt2}1}{\ \ 3+2\sqrt2}=\dfrac{3+2\sqrt2-3+2\sqrt2}{(3-2\sqrt2)(3+2\sqrt2)} =\dfrac{4\sqrt2}{9-8}=\dfrac{4\sqrt2}{1}=4\sqrt2$