Question

Va rog rezolvati in R ecuatia , va rog foarte mult

P.S "Sper ca acum se vede mai bine"

Answer 1

$\left|7\dfrac{1}{4}-3,2x\right|\cdot\sqrt{\dfrac{1-x}{x^2}}=0;\\\\Condi\c{t}ia\;de\;existen\c{t}\breve{a}\;a\;radicalului:\;\dfrac{1-x}{x^2}\geqslant 0\Rightarrow1-x\geqslant0,\;deci\;x\leqslant 1\\\\(am\;\c{t}inut\;cont\;de\;faptul\;c\breve{a}\;x^2\geqslant0);\\\\Dac\breve{a}\;produsul\;a\;2\;termeni\;este\;nul,\;atunci\;fiecare\;termen\;in\;parte\;este\;nul:\\\\\left|7\dfrac{1}{4}-3,2x\right|=\left|\dfrac{7\cdot 4+1}{4}-\dfrac{32}{10}x\right|=\left|\dfrac{29}{4}-\dfrac{16}{5}x\right|=0\Rightarrow\dfrac{29}{4}-\dfrac{16}{5}x=0\Rightarrow\\\\\Rightarrow x_1=\dfrac{29\cdot5}{4\cdot 16}=\dfrac{145}{64}.\;Apoi\;\sqrt{\dfrac{1-x}{x^2}}=0\Rightarrow1-x=0,\;deci\;x_2=1.$

Green eyes.