Question

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Efectuati prin metoda mersului invers:
1)a:7:2:5=8
2)ax3:9:9=1
3)ax2x3x5=780
4)a:5x6:2=450
5)7xa-35x12=378
6)945:a+63x20=1269

Answer 1

salut iti raspund din nou
1)8x2x7=112
2)1x9x9:3=27
3)780:5:3:2=26
4)450x2:6x5=750
5)378:12x35:7=157 rest 5
6)1269:20-63x945=425 rest 25

Answer 2

1)a:7=8x2x5
=a:7=16x5
=a:7=80
a=80x7
a=560
verificare:560:7=80

2)Ax2=780:5:3
Ax2=156:3
Ax2=52
a=52:2
a=26
verificare:26x2=52

3)Ax3:9:9=1
Ax3=9x9x1
Ax3=81x1
Ax3=81
a=81:3
a=27
ver.:27x3=81

4)a:5x6:2=450
a:5=450:6x2
a:5=75x2
a:5=150
a=150x5
a=750
ver.:750:5=150

5)7xA-35x12=378
7xA-420=378
7xA=378+420
7xA=798
a=798:7
a=114
ver.:114x7=798

6)945:a+63x20=1.269
945:a+1.260=1.269
945:a=1.269-1.260
945:a=9
a=945:9
a=105
ver.:945:105=9