Question

Va rog sa aflati aria si perimetrul trapezului isoscel​

Answer 1

sinA = BB'/AB

sin60 = BB'/12

√3/2 = BB'/12 => BB' = 6√3 cm

cnf T30° => AB' = AB/2 = 6 cm

AD = 2AB' + BC = 2×6 + 14 = 12 + 14 = 26 cm

A = (BC+AD)/2×BB'

= (14 + 26)/2×6√3

= 120√3 cm²

P = AB+BC+CD+AD

= 12+14+12+26

= 64 cm