Question

Va rog sa imi spuneti si mie cum se face ca ma chinui si nu pricep cum se face:[(3+3)x3-3+3x(3+3:3)]:3-3x3+3:3x1+3:1=

Answer 1

(6×3-3+3×3+1):3-9+1×1+3:1= (18-3+9+1):3-9+1+3= (15+10):3-10+3= 25:3-13=

Answer 2

se calculeaza mai intai parantezele (    ), apoi [ ]
[6x3-3+3x(3+1)]:3-3x3+3:3x1+3:1=
[18-3+3x4]:3-3x3+3:3x1+3:1=
[18-3+12]:3-3x3+3x1+3:1=
[15+12]:3-3x3+3x1+3:1=
27:3-3x3+3x1+3:1=
calculezi apoi inmultirile si impartirile
9-9+3+3=
0+3+3=
3+3=
6