Question

Va rog sa ma ajtati!Cat mai detaliat,nu dati rezultatul si gata!

1. Stabiliti valoarea de adevar a urmatoarelor afirmatii:

a) 2×3²+5²:5⁰+4²×3-(6⁴)⁶:2²²:(3⁴)⁶+5655:435=100

0
b) (2⁶)⁵×{3⁴×28-[3-(2³×³-3²×10²-5²:(1+4)²]:10⁴-2² ×3⁴} < 2⁷ ×4⁵ ×3²⁵=


2) Calculati:

a) 555³-125×111³=

b) (1+2+2²+....+2⁹⁹):(2¹⁰⁰-1)=

Answer 1

1. a) 2*9+25:1+16*3-6^24:2^22:3^24+13=
= 18+25+48+2^2+13=
=108 >< 100 (F)

b) nu inteleg 2^3x^3?

2)a) (5*111)^3 - 5^3*111^3= 5^3*111^3-5^3*111^3=0
b) calculam prima paranteza astfel: adunam si scadem 1
1+1+2+2^2+....+2^99-1=
=2+2+2^2+2^3+......2^99-1=
=2^2+2^2+2^3+....+2^99-1=
=2*2^2+2^3+....+2^99-1=
=2^3+2^3+.....2^99-1=
=............
=2^100-1

Parantezele sunt egale, deci impartirea lor da 1



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* inseamna inmultit
>< inseamna diferit (egal taiat)