Question

Va rog sa ma ajutati. 0,2+1,(3); 2,5+0,(7); 4,25+0,1(6); 12,25+0,(36); 1,2(3)+0,25

Answer 1

0,2+1,(3)=2/10+(13-1)/9=1/5+12/9=1/5+4/3=(3+4×5)/15=23/15=1,5(3)

2,5+0,(7)=25/10+7/9=5/2+7/9=(5×9+2×7)/9=(45+14)/18=59/18=3,2(7)

4,25+0,1(6)=425/100+(16-1)/90=17/4+15/90=17/4+1/6=(17×3+1×2)/12=
=53/12=4,41(6)

12,25+0,(36)=1225/100+36/99=49/4+4/11=(49×11+4×4)/44=(539+16)/44=
=555/44=12,61(36)

1,2(3)+0,25 =(123-12)/90+25/100=111/90+1/4=37/30+1/4=(37×2+1×15)/60=
=(74+15)/60=89/60=1,48(3)