Question

va rog sa ma ajutati 10×{24^2:576+3[(3^2×2^15):(3^29×2^15)+1^21]}:13

Answer 1

Răspuns: $\bf \pink{\underline{~10~}}$

Explicație pas cu pas:

$\bf 10\cdot\bigg\{24^2:576+3\cdot\Big[\big(3^{2}\cdot2\big)^{15}:\big(3^{29}\cdot2^{15}\big)+1^{21}\Big]\bigg\} : 13 =$

$\bf 10\cdot\bigg\{576:576+3\cdot\Big[\big(3^{2\cdot 15}\cdot2^{15}\big):\big(3^{29}\cdot 2^{15}\big)+1\Big]\bigg\} : 13 =$

$\bf 10\cdot\bigg\{576:576+3\cdot\Big[\big(3^{30}\cdot2^{15}\big):\big(3^{29}\cdot2^{15}\big)+1\Big]\bigg\} : 13 =$

$\bf 10\cdot\bigg\{576:576+3\cdot\Big[\big(3^{30-29}\cdot2^{15-15}\big)+1\Big]\bigg\} : 13 =$

$\bf 10\cdot\bigg\{576:576+3\cdot\Big[\big(3^{1}\cdot2^{0}\big)+1\Big]\bigg\} : 13 =$

$\bf 10 \cdot \big(1 + 3\cdot4\big) : 13 =$

$\bf 10 \cdot 13 : 13 =$

$\bf \pink{\underline{~10~}}$

$==pav38==$