Question

va rog sa ma ajutati​

Answer 1

Răspuns:

Explicație pas cu pas:

$\bigg(\dfrac{3}{7} \bigg)^{8} \cdot \bigg(\dfrac{3}{7} \bigg)^{13} = \bigg(\dfrac{3}{7} \bigg)^{8+13} =\bf \bigg(\dfrac{3}{7} \bigg)^{21}$

$\dfrac{12^{5}}{14^{5}} \cdot \bigg(\dfrac{6}{7} \bigg)^{7} = \bigg(\dfrac{12}{14} \bigg)^{5} \cdot \bigg(\dfrac{6}{7} \bigg)^{7} = \bigg(\dfrac{6}{7} \bigg)^{5} \cdot \bigg(\dfrac{6}{7} \bigg)^{7} = \bigg(\dfrac{6}{7} \bigg)^{5+7} =\bf \bigg(\dfrac{6}{7} \bigg)^{12}$

$\dfrac{1}{32} \cdot \bigg(\dfrac{1}{2} \bigg)^{23} = \dfrac{1^{5}}{2^{5}} \cdot \bigg(\dfrac{1}{2} \bigg)^{23} = \bigg(\dfrac{1}{2} \bigg)^{5} \cdot \bigg(\dfrac{1}{2} \bigg)^{23} = \bigg(\dfrac{1}{2} \bigg)^{5+23} =\bf \bigg(\dfrac{1}{2} \bigg)^{28}$