Question

Vă rog sa mă ajutati

Answer 1

\frac{{(4x\times {2}^{4}x\times {2}^{5})}^{2}}{{({2}^{3})}^{7}}+\frac{{({2}^{5}x\times {2}^{3})}^{2}}{{({2}^{5})}^{3}}
\\
\frac{{(4x\times 16x\times {2}^{5})}^{2}}{{({2}^{3})}^{7}}+\frac{{({2}^{5}x\times {2}^{3})}^{2}}{{({2}^{5})}^{3}}
\\
\frac{{(4\times 16x\times x\times {2}^{5})}^{2}}{{({2}^{3})}^{7}}+\frac{{({2}^{5}x\times {2}^{3})}^{2}}{{({2}^{5})}^{3}}
\\
\frac{{(64{x}^{2}\times {2}^{5})}^{2}}{{({2}^{3})}^{7}}+\frac{{({2}^{5}x\times {2}^{3})}^{2}}{{({2}^{5})}^{3}}
\\
\frac{{(64\times {2}^{5}{x}^{2})}^{2}}{{({2}^{3})}^{7}}+\frac{{({2}^{5}x\times {2}^{3})}^{2}}{{({2}^{5})}^{3}}
\\
\frac{{(64\times {2}^{5}{x}^{2})}^{2}}{{({2}^{3})}^{7}}+\frac{{({2}^{8}x)}^{2}}{{({2}^{5})}^{3}}
\\ ETC... Raspunsul este
\frac{4194304{x}^{4}}{{2}^{21}}+2{x}^{2}