Question

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Answer 1

2. a)
$5 \sqrt{11 } + 8 + 2 \sqrt{11} =$
$\sqrt{11} (5 + 2) + 8 =$
$7 \sqrt{11} + 8$
b)
$16 \sqrt{2} + 2 \sqrt{2} - 9 \sqrt{2} - 5 \sqrt{2} + 11 \sqrt{2 = }$
$\sqrt{2} (16 + 2 - 9 - 5 + 11) =$
$15 \sqrt{2}$
c)
$\sqrt{2} - 3 + 5 \sqrt{2} + 5 =$
$\sqrt{2} (1 + 5) - 3 + 5 =$
$6 \sqrt{2} + 2$
d)
$8.1 \sqrt{2} - 4.7 \sqrt{2} =$
$3.4 \sqrt{2}$

Answer 2

2) 
a) 5√11+8+2√11=8+7√11
b) 16√2+2√2-9√2-5√2+11√2=15√2
=18√2-9√2-5√2+11√2=
=9√2-5√2+11√2=
=4√2+11√2=
=15√2

c) √2-3+5√2+5=6√2+2=2(3√2+1)
d) 8,1√2-4,7√2=3,4√2

3)
a) 6√2+2√16·√2-6√2³+2√3²·√2=8√2
=6√2+2·4√2-6·2√2+2·3√2=
=6√2+8√2-12√2+6√2=
=14√2-12√2+6√2=
=2√2+6√2=
=8√2

b) √72-√18-2√2=√2
=√3²·√2³-√3²·√2-2√2=
=3·2√2-3√2-2√2=
=6√2-3√2-2√2=
=3√2-2√2=
=√2

c)  2√50-√98-3√2=0
=2√25·√2-√49·√2-3√2=
=2·5√2-7√2-3√2=
=10√2-7√2-3√2=
=3√2-3√2=
=0

d) √50-√45-√32+√320=
=√25·√2-√3²·√5-√16·√2+√16·√4·√5=
=5√2-3√5-4√2+4·2√5=
=√2-3√5+8√5=
=√2+5√5

e)  √18-2√3+√98+√75=
=√3²·√2-2√3+√7²·√2+√5²·√3=
=3√2-2√3+7√2+5√3=
=10√2+3√3

f)  √27-2√12+√75=4√3
=√3²·√3-2√2²·√3+√5²·√3=
=3√3-2·2√3+5√3=
=3√3-4√3+5√3=
=-√3+5√3=
=4√3