Question

Va rog sa ma ajutati

Answer 1

cazul I

5m(<A)=5(<B)=2m(<C)=k

m(<A)=m(<B)=k/5; m(<C)=k/2

m(<A+<B+<C)=180°

k/5+k/5+k/2=180°

9k=1800° =>k=200°

m(<A)=m(<B)=200/5=40°

m(<C)=200/2=100°

cazul II

2m(<A)=2(<B)=5m(<C)=k

m(<A)=m(<B)=k/2; m(<C)=k/5

m(<A+<B+<C)=k/2+k/2+k/5=180°

6k=900 => k=150

m(<A)=m(<B)=150/2=75°

m(<C)=150/5=30°

R: 40°,40° si 100°    sau   75°, 75° si 30°