Question

Va rog sa ma ajutati!!

Answer 1

MNH3=14+3=17--------> 1mol=17 g  NH3   [17g/moli  ]

MHNO3=1+14+3.16=63------->1mol=63g HNO3

MCuSO4=64 +32 + 4.16=160 ------------>1mol =  160 g

n=m:M

m=n.M

m=o,5 moli .160g/moli=80 g CuSO4

M K2SO4=2.39 +32+ 4.16=174 -----------> 1mol=174 g K2SO4

MAl2 (SO4)3=2.27 + 3.32 + 12.16=342------------->1mol=342g

MCuCO3=64 +12 + 3.16=124-------->1mol=124g

MH2SO3=2+32+3 .16=82--------->1mol=82g

MZnO=65+16=81--------->1mol=81 g

n=m:M

m=n.M

m=5moli . 81g/moli=405 g ZnO

MNaOH=23+16 +1=40----------> 1mol=40g