Question

Va rog sa ma ajutati!!!​

Answer 1

$(x+1)^{2} +2(x-2)(x+2)=(3x-1)(x-3)+2$

$x^{2} +2x+1+2(x^{2} -4)=3x^{2} -10x+3+2$

$x^{2} +2x+1+2x^{2} -8=3x^{2} -10x+5$

se reduc termenii cu x^2

$2x-7=-10x+5$

2x-7+10x-5=0

12x-10=0

x-1=0

x=1