Question

Va rog sa ma ajutati.​

Answer 1

Explicație pas cu pas:

1. $\sqrt{ \frac{1}{4} } + \sqrt{ \frac{1}{9} } + \sqrt{ \frac{49}{36} }$

${1}^{2} = 1 \\ {2}^{2} = 4 \\ {3}^{2} = 9 \\ {7}^{2} = 49 \\ {6}^{2} = 36$

$\sqrt{ \frac{ {1}^{2} }{ {2}^{2} } } + \sqrt{ \frac{ {1}^{2} }{ {3}^{2} } } + \sqrt{ \frac{ {7}^{2} }{ {6}^{2} } }$

$\frac{1}{2} + \frac{1}{3} + \frac{7}{6}$

$\frac{3}{6} + \frac{2}{6} + \frac{7}{6}$

$\frac{3 + 2 + 7}{6}$

$\frac{12}{6}$

$= 2$