Question

va rog sa ma ajutati calculati 3supra20 minus 1supra40=,7supra9 minus 1supra36=,17supra12 minus 7supra24=

Answer 1

$\frac{3}{20} - \frac{1}{40} = \frac{6-1}{40} \frac{5}{40} = \frac{1}{8}$

$\frac{7}{9} - \frac{1}{36} = \frac{28-1}{36} = \frac{27}{36} = \frac{9}{12} = \frac{3}{4}$

$\frac{17}{12} - \frac{7}{24} = \frac{34-7}{24} = \frac{27}{24}$