Question

Va rog sa ma ajutati cu aceasta limita...

Answer 1

1/1*3=1/2(1/1-1/3)

1/2*4=1/2*(1/2-1/4)

1/3*5=1/2*(1/3-1/5)

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1/n*(n+2)=1/n-1/(n+2)

______________---------------------Se   aduna    termen   cu    termen

1/1*3+1/2*4+,,,+1/n(n+2)=1/2(1+1/2+1/n

lim(1/1*3+1/2*4+,,,+1/n*(n+2)=lim1/2(3/2+1/n)=3/4 pt  ca 1/n→0