Question

vă rog să mă ajutați dau 100 puncte recompensa ​

Answer 1

Răspuns:

a) 1/2

b) 5/7

c) 1/3

d) 37/4

Explicație pas cu pas:

a)

$= [\frac{3}{4} +\frac{2}{3} :(\frac{3}{4} -\frac{2}{4} )]*\frac{6}{41} =(\frac{3}{4} +\frac{2}{3} :\frac{1}{4} )*\frac{6}{41} =$

$=(\frac{3}{4} +\frac{2}{3}*4 )*\frac{6}{41} =(\frac{3}{4} +\frac{8}{3})*\frac{6}{41}=$

$=\frac{9+32}{12}*\frac{6}{41}=\frac{41}{12}*\frac{6}{41}=\frac{1}{2}$

b)

$=[\frac{7}{15} *\frac{15}{14} +\frac{3}{2} :(\frac{9}{4} -\frac{3}{2} )]*\frac{2}{7} =[\frac{1}{2} +\frac{3}{2} :(\frac{9}{4} -\frac{6}{4} )]*\frac{2}{7} =$

$=(\frac{1}{2} +\frac{3}{2} :\frac{3}{4})*\frac{2}{7} =(\frac{1}{2} +\frac{3}{2} *\frac{4}{3})*\frac{2}{7} =$

$=(\frac{1}{2} +\frac{4}{2})*\frac{2}{7} =\frac{5}{2} *\frac{2}{7}=\frac{5}{7}$

c)

$=(\frac{17}{3} +\frac{14}{9} -2):\frac{47}{3} =(\frac{51}{9} +\frac{14}{9} -\frac{18}{9} )*\frac{3}{47} =\frac{47}{9} *\frac{3}{47}=\frac{1}{3}$

d)

$=[4+\frac{20}{3} -\frac{9}{4} *(\frac{6}{9} -\frac{2}{9} )]:\frac{29}{6} +\frac{29}{4} =(4+\frac{20}{3}-\frac{9}{4} *\frac{4}{9} )*\frac{6}{29} +\frac{29}{4}=$

$=(4+\frac{20}{3}-1)*\frac{6}{29} +\frac{29}{4}=(3+\frac{20}{3})*\frac{6}{29} +\frac{29}{4}=\frac{29}{3}*\frac{6}{29} +\frac{29}{4}=$

$=2+\frac{29}{4}=\frac{8+29}{4} =\frac{37}{4}$