Question

VA ROG SA MA AJUTAȚI dau coroană .​

Answer 1

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a)

$2 \sqrt{3} \times (2 \sqrt{2} + 2 \sqrt{3} ) - 4 \sqrt{6} = 4 \sqrt{6} + 12 - 4 \sqrt{6} = 12$

b)

$2 \times 2 \sqrt{2} (10 \sqrt{2} - 18 \sqrt{2} + 9 \sqrt{2} ) = 2 \times 2 \sqrt{2} \times \sqrt{2} = 8$

c)

$6 \sqrt{5} + 2 \sqrt{5} \times (1 - \sqrt{2} ) - 8 \sqrt{5} + 3 \sqrt{10} = 6 \sqrt{5} + 2 \sqrt{5} - 2 \sqrt{10} - 8 \sqrt{5} + 3 \sqrt{10} = \sqrt{10}$

d)

$\frac{ \sqrt{18} }{6} - \frac{2 \sqrt{10} }{5} \times \frac{ \sqrt{5} }{4} - \sqrt{8} = \frac{ \sqrt{2} }{2} - \frac{ \sqrt{2} }{2} - 2 \sqrt{2} = - 2 \sqrt{2}$

e)

$0.5 \times 2 \sqrt{6} - \sqrt{6} + 2 \sqrt{3} + 3 \sqrt{6} \div 3 \sqrt{2} = \sqrt{6} - \sqrt{6} + 2 \sqrt{3} + 2 \sqrt{3} = 4 \sqrt{3}$

f)

$( - 2 \sqrt{10} - 3 \sqrt{10} + 10 \sqrt{10} ) ^{3} \div ( - \sqrt{3125} = (5 \sqrt{10)} ^{3} \div ( - 25 \sqrt{5} ) = 1250 \sqrt{10} \div ( - 25 \sqrt{5} ) = - 50 \sqrt{2}$