Question

Vă rog să mă ajutați
Dau coroana​

Answer 1

Răspuns:

36. a) aducem la acelasi numitor 4

$\frac{2*1+3}{4}$= $\frac{5}{4}$

b) $\frac{5*2}{6} - \frac{4}{6}$= $\frac{10-4}{6} =\frac{6}{6} =1$

c) 10=2*5    12=$2^{2}$ *3    20= $2^{2}$ *5      n.c= $2^{2}$ *3*5= 60

$\frac{7*6 - 8*5+9*3}{60}$= $\frac{42-40+27}{60}$= $\frac{29}{60}$

d) $\frac{20}{27}$+ $\frac{2}{3} *\frac{12}{8}$= $\frac{20}{27}$ + $\frac{1*4}{1*4}$=  $\frac{20}{27}$ + 1= $\frac{20+27}{27}$= $\frac{47}{27}$

e) $\frac{6}{3} - \frac{15}{8} - \frac{1}{2}$= 2- $\frac{15}{8} -\frac{1}{2}$= $\frac{16-15-1}{8} =0/8=0$

f) $\frac{5}{4} - \frac{3}{4} *\frac{12}{8} + \frac{3}{4}$ + 8 +9-1= $\frac{5}{4} - \frac{9}{8} - \frac{3}{4} + 16$ = $\frac{10-9+6+16*8}{8}$= $\frac{7+128}{8}$= $\frac{135}{8}$

g)$\frac{1}{4} + \frac{8}{8} - \frac{1}{4}$= 0+1=1

37. a) 24= $2^{3}$*3

56= $2^{3}$*7

cmmdc(24, 56)= $2^{3}$=8

b) 5= $5^{1}$    15=$3^{1} *5^{1}$    30= $2^{1} *3^{1} *5^{1}$   45= $3^{2} *5$

cmmdc(5, 15,30,45)= 5

c) 450= 2*$3^{2} *5^{2}$        1300= 13* $2^{2} *5^{2}$

cmmdc(450, 1300)= 2*$5^{2}$= 50   se ia factorii comuni la puterea cea mai mica

38. a) cmmmc= $2^{3} *3*7$= 8*21=168

b) cmmmc= $2^{1} *3^{2} *5$=90

c) 4500= $2^{2} *3^{2} *5^{3}$    130= 13* 2*5

cmmmc= $2^{2} *3^{2} *5^{3}$ *13=58500

40 . a)2 + [ 76-2 *(20+20):5 - 12=  2+ (76-2 *40:5-12)= 2 + (76-2*8-12)=

2+ 76-16-12= 2+48= 50

b) (111 +22+66):1+10= (111+88):1+10 = 199:1+10= 199+10=209

41. a) M3= 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51

b) M5=5, 10, 15, 20, 25, 30, 35, 40, 45, 50

c) M6= 6, 12, 18, 24, 30, 36, 42, 48