Question

Vă rog să ma ajutați dau coroană,VĂ ROG URGENTTTT​

Answer 1

Răspuns: 1880

Explicație pas cu pas:

Salutare!

$\bf 10^{3}:5^{2}+10\cdot\{2^{10}:64+2^{3}\cdot[1035:(5\cdot3^{2})-(2^{37}\cdot7^{37})^{2}:(4^{36}\cdot 49^{37}):2]\} =$

$\bf 1000:25+10\cdot\{2^{10}:2^{6}+2^{3}\cdot[1035:(5\cdot 9)-(2^{37\cdot2}\cdot7^{37\cdot2}):((2^{2})^{36}\cdot (7^{2})^{37}):2]\} =$

$\bf 40+10\cdot\{2^{10-6}+2^{3}\cdot[1035:45-(2^{74}\cdot7^{74}):(2^{2\cdot36}\cdot 7^{2\cdot37}):2]\} =$

$\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{74}\cdot7^{74}):(2^{72}\cdot 7^{74}):2]\} =$

$\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{74-72}\cdot7^{74-74}):2]\} =$

$\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{2}\cdot7^{0}):2]\} =$

$\bf 40+10\cdot\{2^{4}+2^{3}\cdot[23-(2^{2}\cdot 1):2]\} =$

$\bf 40+10\cdot[2^{4}+2^{3}\cdot(23-2^{2}:2)] =$

$\bf 40+10\cdot[2^{4}+2^{3}\cdot(23-2^{2-1})] =$

$\bf 40+10\cdot[2^{4}+2^{3}\cdot(23-2)] =$

$\bf 40+10\cdot(2^{4}+2^{3}\cdot 21) =$

$\bf 40+10\cdot(16+8\cdot 21) =$

$\bf 40+10\cdot(16+168) =$

$\bf 40+10\cdot 184 =$

$\bf 40 + 1840=$

$\boxed{\bf 1880}$

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