Question

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Answer 1

a) (3x+1)²=100

3x+1=±√100

3x+1=±10

=>3x+1=-10 sau 3x+1=10

3x=-11 3x=9

x=-11/3 x=3

S={-11/3,3}

b) (x-2019)^2=1

x-2019=±√1

x-2019=±1

=> x-2019=-1 sau x-2019=1

x=2018 x=2020

S={2018,2020}

c) 4/x=x/16

x²=64

x=±√64

x=±8

S={-8,8}

d)2x/16=18/x

2x²=288

x²=144

x=±√144

x=±12

S={-12,12}

e)3x/2=98/3x

9x²=196

x²=196/9

x=±14/3

S={-14/3,14/3}

f)144*x²=(√7+2)²

±√144x²=√7+2

±12x=√7+2

=>√7+2=-12x

x=(√7+2)/-12

√7+2=12x

x=(√7+2)/12

S={(√7+2)/-12; (√7+2)/12}

g) 121*x²=(√11+3)²

±√121x²=√11+3

±11x=√11+3

=>√11+3=11x

x=(√11+3)/11

√11+3=-11x

x=(√11+3)/-11

S={(√11+3)/-11; (√11+3)/11}

h) (√13-7)²=625*x²

√13-7=±25x

=>√13-7=-25x

x=(√13-7)/-25

√13-7=25x

x=(√13-7)/25

S={(√13-7)/-25; (√13-7)/25}