Question

vă rog să mă ajutați la exercițiile acestea
$a \div8 + 2000 = 2003$
$(394 - 123 - a) \div 2 = 108$
$6 + \times 5 \div 10 + a = 296$
${(124 + 692) - 400 \times 2 } \div a = 4$

Answer 1

a÷8+2000=2003

a÷8=2003-2000

a÷8=3=> a=3×8=24

(394-123-a)÷2=108

271-a=108×2

271-a=216

a=271-216

a=55

6×5÷10+a=296

30÷10+a=296

3+a=296

a=296-3

a=293

(124+692)-400×2÷a=4

816-800÷a=4

800÷a=812

a=800÷812=

Answer 2

a÷8+2000=2003
a÷8=2003-2000
a÷8=3
a=3×8
a=24

(394-123-a)÷2=108
394-123-a=108×2
394-123-a=216
271-a=216
a=271-216
a=55

6×5÷10+a=296
30÷10+a=296
3+a=296
a=296-3
a=293

(124+692)-400×2÷a=4
816-800÷a=4
16÷a=4
a=16÷4
a=4