Question

Va rog sa ma ajutati la exercitiul 16 atasat in poza!

Answer 1

a) x<0  atunci x<0<1 si, 1>x si 1-x>0 deci  |1-x|=1-x

si

-x+2x+1+1-x=2

b) x<5 deci |x-5|=5-x

atunci

x²+1 +5(5-x)-16-x²=1+25-5x-16=26-16-5x=10-5x=-5x+10

c) x>-3 deci |x+3|=x+3

|2x-4|=2|x-2|  dar x<1<2 deci |x-2|=2-x

x<1 atunci |x-1|=1-x

atunci

-(x+3)+|x-1|-2(2-x)=

=-x-3+1-x-4+2x=-2-4=-6