Question

Va rog sa ma ajutati la exercițiul 4 vreu pași cum se rezolva va rogggg

Answer 1

Răspuns:

a) $\sqrt \frac{16}{49} = \frac{\sqrt 16}{ \sqrt 49} = \frac{\sqrt 4^{2} }{ \sqrt 7^{2}} = \frac{4}{7}$

b) $\sqrt \frac{1}{121} = \frac{\sqrt 1}{ \sqrt 121} = \frac{\sqrt 1^{2} }{ \sqrt 11^{2}} = \frac{1}{11}$

c) $\sqrt \frac{64}{169} = \frac{\sqrt 64}{ \sqrt 169} = \frac{\sqrt 8^{2} }{ \sqrt 13^{2}} = \frac{8}{13}$

d) $\sqrt \frac{100}{49} = \frac{\sqrt 100}{ \sqrt 49} = \frac{\sqrt 10^{2} }{ \sqrt 7^{2}} = \frac{10}{7}$

e) $\sqrt \frac{144}{361} = \frac{\sqrt 144}{ \sqrt 361} = \frac{\sqrt 12^{2} }{ \sqrt 19^{2}} = \frac{12}{19}$

f) $\sqrt \frac{1}{400} = \frac{\sqrt 1}{ \sqrt 400} = \frac{\sqrt 1^{2} }{ \sqrt 20^{2}} = \frac{1}{20}$

g) $\sqrt \frac{225}{16} = \frac{\sqrt 225}{ \sqrt 16} = \frac{\sqrt 15^{2} }{ \sqrt 4^{2}} = \frac{15}{4}$

h) $\sqrt \frac{49}{900} = \frac{\sqrt 49}{ \sqrt 900} = \frac{\sqrt 7^{2} }{ \sqrt 30^{2}} = \frac{7}{30}$

i) $\sqrt \frac{1600}{81} = \frac{\sqrt 1600}{ \sqrt 81} = \frac{\sqrt 40^{2} }{ \sqrt 9^{2}} = \frac{40}{9}$

j) $\sqrt \frac{9}{196} = \frac{\sqrt 9}{ \sqrt 196} = \frac{\sqrt 3^{2} }{ \sqrt 14^{2}} =\frac{3}{14}$