Question

va rog sa ma ajutati !! la mate

Answer 1

|x-1|=9

x=1=9...x=10

x-1=-9........x=-8

x²+2x+1+y²-4y+4=0

(x-1)²+(y-2)²=0

x=1 si y=2

..............

407+2√5-3√2-(3√12-2√5)=

407+2√5+3√2-6√3+2√5=407+4√5+3√2-6√3 complet ciudat...

am tinut cont ca

2√5>3√2 si ca (3√12>2√5)

Answer 2

$\it \sqrt{(x-1)^2} = 9 \Leftrightarrow |x-1| =9 \Leftrightarrow x-1=\pm9 \Leftrightarrow x-1\in\{-9,\ 9\}|_{+1} \Leftrightarrow\\ \\ \Leftrightarrow x\in\{\ -8,\ 10\}$