Question

Va rog sa ma ajutati la sub h

Answer 1

[tex]\it (2^{27}: 4^6+25^4\cdot2 ) : (4^7+5^8) = \\\;\\ = [2^{27}+(2^2)^6+(5^2)^4\cdot2]:[(2^2)^7+5^8] = [/tex]

[tex]\it = (2^{27} :2^{12} +5^8\cdot2) : (2^{14} +5^8) = (2^{15} +5^8\cdot2) : (2^{14} +5^8 ) = \\\;\\ = 2\cdot(2^{14} +5^8):(2^{14} +5^8) = 2\cdot1=2[/tex]