Question

Va rog sa ma ajutati,nu am inteles cum sa calculez,dau coroana

Se cer nr de moli si nr particule din:
a)3,2kg O
b)4,4g CO3
c)34g NH3​

Answer 1

Răspuns:

Explicație:

a ) MO2=2Ao=2*16 =32 u.a.m

n=m/M=3,2Kg/32Kg/Kmol=0.1 Kmol

1kmol............6,023*10 ²³k particule

0,1............................x

b) MCO2=AC+2AO=12+2*16=44u.a.m

n=m/M=4,4 g/44g/mol=0,1 moli

1mol ...............6,023*10 ²³

0,1mol...............x

c) M=AN+3AH=14+3*1=17 u.a.m

n=m/M=34g/17 g/mol=2 moli

1mol.........................6,023*10 ²³

2moli.................................x