Question

Va rog sa ma ajutati..Si cat mai repede!
Multumesc anticipat!
1. 336:(7 la a doua + 0 la a saptea - 5 la a doua)= 
2. b la 13 x b x b la 12 x b la 20 = 
3. 16 la 4 x 4 la 10 x 64 la 5 = 
4. c la 58 : c la 39 : c la 9 = 
5. 125 la 42 : 25 la 63 = 
6. (8 la 37 x 81 la 25) : (16 la 27 x 27 la 33)
7. 2 la 1 x 2 la 2 x 2 la 3 x 2 la 4 x...x2 la 45= 

Answer 1

$1).336:(7^2+0^ 7-5^2)=336:(49+0-25)=336:24=14 \\ 2).b^1^3*b*b^1^2*b^2^0=b^1^3^+^1^+^1^2^+^2^0=b^4^6 \\ 3).16^4*4^1^0*64^5=(4^2)^4*4^1^0*(4^3)^5=4^8*4^1^0*4^1^5= \\ =4^8^+^1^0^+^1^5=4^3^3 \\ 4).c^5^8:c^3^9:c^9=c^5^8^-^3^9^-^9=c^1^0 \\ 5).125^4^2:25^6^3=(5^3)^4^2:(5^2)^6^3=5^1^2^6:5^1^2^6=5^1^2^6^-^1^2^6=5^0=1 \\ 6).(8^3^7*81^2^5):(16^2^7*27^3^3)= [(2^3)^3^7*(3^4)^2^5]:[(2^4)^2^7*(3^3)^3^3]= \\ =(2^1^1^1*3^1^0^0):(2^1^0^8*3^9^9)= 2^1^1^1^-^1^0^8*3^1^0^0^-^9^9=2^3*3=8*3=24$
$7).2^1*2^2*2^3*2^4*...*2^4^5=1+2+3+4+...+45= \\ =45(45+1):2=(45*46):2=2070:2=1035=2^1^0^3^5$