Question

Va rog sa ma ajutati si pe mine!!!
1)7·(x+2)-3·(x-4)-x=2·(x+5)+46
2)8·(x+1)-4·(x-3)-x=2·(x+5)
3)4x+12-3·(x+4)=(x+5)

Answer 1

1) 7x+14-3x+12-x=2x+10+46
3x+26=2x+56
3x-2x=56-26
x=30

2) 8x+8-4x+12-x=2x+10
3x+20=2x+10
3x-2x=10-20
x= -10

3) 4x+12-3x-12=x+5
x=x+5
x-x=5
0=5 (cred ca ai uitat ceva, posibil la (x+5) ca nu este bun rezolvarea

Answer 2

1) 7·(x+2)-3·(x-4)-x=2·(x+5)+46
7X+14-3X+12-X = 2X+10+46
3X-2X = 56-14-12
X = 30


2) 8·(x+1)-4·(x-3)-x=2·(x+5)
8X+8 - 4X + 12 - X = 2X + 10
3X - 2X = 10- 8 - 12
X = -10


3) 4x+12-3·(x+4)=(x+5)
4X + 12 - 2X - 12 = X + 5
2X - X = 5
X = 5