Question

va rog sa ma ajutati si pe mine cu ex 4

Answer 1

a)2√3-2√12= 2√3-2×2√3=2√3×(1-2)=2√3×(-1)=-2√3×1=-2√3
b)4√7-2√7+√7= 4√7-2√7+7=3√7
c)-√27+3√3=-3√3+3√3= 0
d)√8/9-√2+1/6×√2=√8/√9-√2+√2/6=2√2/3-√2+√2/6=/4√2-6√2+√2/6= -√2/6
e)6√2+2√32-6√8=6√2+2×4√2-6×2√2=6√2+8√2-12√2=2√2
f)=-√+4√3-2×5√3+10√3=-√3+4√2-10√3+10√3=3√3
g)=√5+2√6-2√5-5√6+5√5= 4√5-3√6...................bafta