Question

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$( {3}^{2} - {2}^{3} ) {}^{2} \times ( {8}^{5} \div {4}^{7} ) {}^{2} =$

Answer 1

   (3^2-2^3)^2 x (8^5:4^7)^2 = 
= (9-8)^2 x [(2^3)^5 : (2^2)^7]^2 =
= 1^2 x (2^15 : 2^14)^2 = 
= 1 x (2^1)^2 = 
= 2^2 =
= 4

Answer 2

$( {3}^{2} - 2 {}^{3} ) ^{2} \times (8 {}^{5} \div {4}^{7} )^{2} = \\ = (9 - 8) ^{2} \times (32768 \div 16384) = \\ = 1 \times 2 = \\ = 2$