Question

Va rog sa ma ajutati! va multumesc.
In triunghiul ABC avem AB=5, AC=1+AB si B=30°. Calculati sinC.

Answer 1

$AC=6. \\ \\ \dfrac{AC}{\sin B}=\dfrac{AB}{\sin C} \\ \\ \\ \dfrac{6}{\frac{1}{2}}=\dfrac{5}{\sin C} \\ \\ \\ \sin C=\frac{5}{12}$