Question

Va rog să-mi efectuațu acest exercițiu , mulțumesc !

Answer 1

Răspuns:

Explicație pas cu pas:

$x=\sqrt{\dfrac{1}{94}[(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{24}-\dfrac{1}{25} )-(\dfrac{1}{25}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{27}+...+\dfrac{1}{49}-\dfrac{1}{50}) }=\sqrt{\dfrac{1}{94}*[(\dfrac{1}{1}-\dfrac{1}{25})-(\dfrac{1}{25}-\dfrac{1}{50})}=\sqrt{\dfrac{1}{94}*[\dfrac{1}{1}-\dfrac{1}{25}-\dfrac{1}{25}+\dfrac{1}{50}] }=\sqrt{\dfrac{1}{94}*\dfrac{50-2-2+1}{50} }= \sqrt{\dfrac{1}{94}*\dfrac{47}{50} }=\sqrt{\dfrac{1}{100} } =\dfrac{1}{10} ~~rational...$