Question

va rog sa răspundeți...........dau inima stea CCOROANA.....​

Answer 1

$\it log_{3}(2x-5)=1 \Rightarrow 2x-5=3^1 \Rightarrow 2x-5=3|_{+5} \Rightarrow 2x=8|_{:2} \Rightarrow x=4\\ \\ \\ log_4(5-3x)=2 \Rightarrow 5-3x=4^2 \Rightarrow 5-3x=16|_{-5} \Rightarrow -3x=11 \Rightarrow x=-\dfrac{11}{3}\\ \\ \\ log_3(x-6)=0 \Rightarrow x-6=3^0 \Rightarrow x-6=1|_{+6} \Rightarrow x=7$