Question

Va rog sa rezolvati acest exercitiu .

*P.S: dau coroană*

Answer 1

Răspuns:

$(-\frac{5}{4})^{-2} : (-\frac{5}{4})^{-6} * [(-\frac{5}{4})^{2} ]^{3} =\\\\(\frac{1}{(-\frac{5}{4})^{2}} : \frac{1}{(-\frac{5}{4})^{6}} * (-\frac{5}{4})^{2*3} =\\\\(\frac{1}{(-\frac{5}{4})^{2}} * \frac{(-\frac{5}{4})^{6}}{1} * (-\frac{5}{4})^{6}\\\\(-\frac{5}{4})^{4} *(-\frac{5}{4})^{6} =\\\\(-\frac{5}{4})^{4*6}=\\\\(-\frac{5}{4})^{24}=\\\\(\frac{5}{4})^{24}$

inversul numarului

$(\frac{5}{4})^{24} = (\frac{5}{4})^{-24}$ $= \frac{1}{(\frac{5}{4})^{24} }$