Question

Va rog sa rezolvati toate cele trei probleme daca puteti!va multumesc daca reusiti

Answer 1

1. cf th Pitagora
BC²=AB²+AC²=30²+40²=2500
BC=50 km

2.AD*BC=AB*AC
AD=AB*AC/BC=15*20/25=12m

3.cf th catetei:
ED²=EG*EF=4*12=48dam  ED= 4√3dam
DF²=GF*EF=8*12=96dam => DF=4√6dam

Daca ma intrebi pe mine, asta e un raspuns stupid referitor la lungimea unui obiect.

Normal ar fi extragand radicalul, si obtinem:
ED=21.91 m=2191cm
si DF= 30.98m=3098 cm