Question

Va rog stie cineva cum se face​

Answer 1

Aplicăm formula radicalilor compusi.

$\it \sqrt{2+\sqrt3}=\sqrt{\dfrac{2+1}{2}}+\sqrt{\dfrac{2-1}{2}}=\dfrac{\sqrt3}{\sqrt2}+\dfrac{1}{\sqrt2}=\dfrac{\sqrt6}{2}+\dfrac{\sqrt2}{2}=\dfrac{1}{2}\sqrt6+\dfrac{1}{2}\sqrt2\\ \\ \\ Deci, a=b=\dfrac{1}{2}$