Question

Va Rog
$\frac{a + 2}{a + 3} \geqslant \frac{2}{3}$
​

Answer 1

Răspuns:

(a+2)/(a+3)≥ 2/3

inmultim mezii cu extremii

3(a+2) ≥ 2(a+3)

3a+6 ≥2a+6

3a-2a ≥ 6-6

a ≥ 0

Answer 2

$\frac{a+2x}{a+3}\geq  \frac{2}{3}$

3(a + 2) ≥ 2(a + 3)

3a + 6 ≥ 2a + 6

3a - 2a ≥ 6 - 6

a ≥ 0

a ∈ [0, +oo)