vă rog toate exercitiile ! nu e obligatoriu să vă grăbiţi. dau coroniţă.
Anexe:
Răspunsuri la întrebare
Răspuns de
1
q)2/3+x+1/2=5-4-x/6
Numitorul comun este 6
4+6x+3=30-24-x
6x+7=6-x
6x+x=6-7
7x=-1 =>x=-1/7
r) 6x/5-x=x/3+8
se aduce la acelasi numitor comun, in acest caz este 15
6x·3-x·15=x·5+8·15
18x-15x=5x+120
3x-5x=120
-2x=120
x=-60
s)1/4*{1/4*[1/4*(1/4*x+1)+4]+1}+4=5
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=5-4
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=1
{1/4*[1/4*(1/4*x+1)+4]+1}=4
1/4*[1/4*(1/4*x+1)+4]=4-1
1/4*[1/4*(1/4*x+1)+4]=3
1/4*(1/4*x+1)+4=12
1/4*(1/4*x+1)=8
1/4*x+1=32
1/4*x=31
x=124
t)0,(6)x+2x-0,(3)=4-2(x+1)+3,(6)
6/9x+2x-3/9= 4- 2x-2+33/9
2/3*x+2x-1/3=4-2x-2+11/3
2/3*x+4x= 2+12/3
2x+12x=6+12
14x=18
x=18/14
x=9/7
Numitorul comun este 6
4+6x+3=30-24-x
6x+7=6-x
6x+x=6-7
7x=-1 =>x=-1/7
r) 6x/5-x=x/3+8
se aduce la acelasi numitor comun, in acest caz este 15
6x·3-x·15=x·5+8·15
18x-15x=5x+120
3x-5x=120
-2x=120
x=-60
s)1/4*{1/4*[1/4*(1/4*x+1)+4]+1}+4=5
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=5-4
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=1
{1/4*[1/4*(1/4*x+1)+4]+1}=4
1/4*[1/4*(1/4*x+1)+4]=4-1
1/4*[1/4*(1/4*x+1)+4]=3
1/4*(1/4*x+1)+4=12
1/4*(1/4*x+1)=8
1/4*x+1=32
1/4*x=31
x=124
t)0,(6)x+2x-0,(3)=4-2(x+1)+3,(6)
6/9x+2x-3/9= 4- 2x-2+33/9
2/3*x+2x-1/3=4-2x-2+11/3
2/3*x+4x= 2+12/3
2x+12x=6+12
14x=18
x=18/14
x=9/7
u)12 intregi 1/3 : {[2 intregi 3/4 : (1 intreg 2/3 + 1 intreg 7/8 · x)] · 8/11 + 1 intreg 2/3 } =5
37/3÷{[11/4 ÷(5/3 + 15/8·x )]·8/11 + 5/3} =5
[11/4÷(5/3 + 15/8·x)]·8/11 + 5/3 = 5/1×3/37 = 15/37
[11/4÷(5/3 + 15/8·x)]·8/11 = 15/37 - 5/3 = - 140/111
11/4÷(5/3 + 15/8·x) = -140/111·11/8 = - 385/222·
5/3 + 15/8·x = -385/222× 4/11 = - 35·2/111 = -70/111
15/8·x = -70/111 - 5/3 = - 255/111 x= -255/111×8/15 =-136/111
mimiiii228:
multumesc mult !
Alte întrebări interesante