Question

va rog urgent afla perechile de numere naturale care au suma 40 si c.m.m.d.c.5.

Answer 1

a + b = 40

a = 5x

b = 5y

5x + 5y = 40

5(x + y) = 40

x + y = 8

• x = 1 => y = 7

a = 5x = 5

b = 5y = 35

• x = 2 => y = 6

a = 5x = 10

b = 5y = 30

cmmdc = 10, solutia nu este viabila

• x =3 => y = 5

a = 5x = 15

b = 5y = 25

• x = 4 => y = 4

a = 5x = 20

b = 5y = 20

cmmdc = 20, solutia nu este viabila

• Vom avea solutiile {5,35} si {15,25}