Question

va rog urgent!!!

Aflati numerele a b c stiind ca sint invers proportionale cu 3 8 12 si ca 4a+2b-3c=64




VA ROG MULT URGENT

Answer 1

{a;b;c} i.p. {3;8;12}
4a+2b-3c=64
a/1/3=b/1/8=c/1/12=K ⇔a=K/3
                                        b=K/8
                                        c=K/12
4K/3+2K/8-3K/12=64 (amplificam fractiile cu 8;3 si 2 ptr a avea acelasi numitor)
32K+6K-6K  =64
      24
32K  =64
24
32K=64x24
32K=1536
K=1536:32
K=48
a=48:3=16
b=48:8=6
c=48:12=4