Question

va rog urgent!!!!dacă se poate pe lung​

Answer 1

3.a)|x-5|=0

x-5=0

x=5

b)|2x+10|=0

2x+10=0

2x=-10

x=-5

4)a)-5-(+3-4)

-5-(-1)

-5+1

4

b)-2×(-3+4)-5×(4-2)

-2×1-5×2

-2-10

-12

5)(-24):(-6)+(-2)×(-3)-(-30):(+5)

4+6+30:5

4+6+6

16

6)169:(-13)²+(-4)²:(+2)³

13²:13²+4²:2³

1+2⁴:2³

1+2

3

7)a)(-3)+(+2)>(-5)+(+3)

-3+2>-2

-1>-2=> (adevarat)

b)(-3)-(-7)<(-5)+(-2)

-3+7<-5-2

4<-7 => (fals)

c)(-2)²<_4

2²<_2²

2<_2 => (adevarat)

d)(-15):(+3)>(-7)(-1)

-5>7 => (fals)