Question

Va rog urgent..dau coroana
-2x la puterea2+5x-2=0
-6x la puterea2-x+1=0

Answer 1

-2x²+5x-2 = 0

a = -2
b = 5
c = -2

∆ = b²-4ac
∆ = 5²-4•(-2)•(-2)
∆ = 25-16
∆ = 9.

x1 = (-b+√∆)/2a
x1 = (-5+3)/-4
x1 = -2/-4
x1 = 1/2.

x2 = (-b-√∆)/2a
x2 = (-5-3)/-4
x2 = -8/-4
x2 = 2.

a(x-x1)(x-x2) = -2(x-1/2)(x-2) = -2(2x/2-1/2)(x-2) = -(2x-1)(x-2).




-6x²-x+1 = 0

a = -6
b = -1
c = 1

∆ = b²-4ac
∆ = 1-4•(-6)
∆ = 1+24
∆ = 25.

x1 = (-b+√∆)/2a
x1 = (1+5)/-12
x1 = 6/-12
x1 = -1/2.

x2 = (-b-√∆)/2a
x2 = (1-5)/-12
x2 = -4/-12
x2 = 1/3.

a(x-x1)(x-x2) = -6(x+1/2)(x-1/3) = -6(2x/2+1/2)(3x/3-1/3) = -(2x+1)(3x-1).




J'espère aidé :)

Answer 2

-2x² + 5x - 2 = 0 => descompun pe 5x = 4x+x !!!
- 2x² +4x +x - 2 = 0 =>  -2x(x-2)+(x-2)= 0 adica: (x-2)(1-2x)=0 
                                                                         ⇒ x-2 = 0 deci x₁=2 si
                                                                             1-2x=0 deci x₂=1/2

-6x² -x + 1 = 0    Δ = 1 - 4*(-6)*1 = 1+24=25 ⇒ √Δ=5 ;
                          x₁=(1+5)/(-12)=6/-12= - 1/2 si
                          x₂=(1 -5)/(-12)=-4/-12 = 1/3