Question

Vă rog urgent,dau coroană,55 puncte
Rezolvaţi ecuaţiile
(x+3)(x-4)=-12
5(x-2)=(3x+2)(x-2)
4x^2-5x+1/x^2+5x-6
Vă rogggg,urgenttt
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Answer 1

1.

$(x+3)(x-4)=-12\\\\x^2-x-12=-12\\\\x^2-x=0\\\\x(x-1)=0\\\\x=0\\\\x-1=0\\\\x=1$

2.

$5\left(x-2\right)=\left(3x+2\right)\left(x-2\right)\\\\5\left(x-2\right)-\left(3x+2\right)\left(x-2\right)=0\\\\-3\left(x-2\right)\left(x-1\right)=0\\\\x-2=0\quad \mathrm\\\\\quad \:x-1=0\\\\x=2, x=1$

3. Ceva ai gresit in conditie cand ai copiat!