Question

VA ROG URGENT DAU COROANA!!! ​

Answer 1

Răspuns:

a)

$=[1+\frac{1}{2} +\frac{1}{4} +\frac{1}{8} ]*\frac{1}{1+2+4+8} =$

$=\frac{8+4+2+1}{8} *\frac{1}{1+2+4+8} = \frac{1}{8}$

b)

$=\frac{3^{13} }{2^{13} } *\frac{3^{8} }{2^{8} } *\frac{2^{19} }{3^{19} } -2=$

$=\frac{3^{2} }{2^{2} } -2 =$

$=\frac{3^{2} -2^{3} }{2^{2} } =\frac{9-8}{4} =\frac{1}{4}$

Explicație pas cu pas: