Question

va rog urgent dau coroana ​

Answer 1

Răspuns:

Explicație pas cu pas:

b) AB^2 =(2-(-3))^2 +(3-1)^2 = 25+4 = 29

AB = √29

c) m = (y2-y1)/(x2-x1)

m = (3-1)/((2-(-3)) = 2/5

d) M( (-3+2)/2; (1+3)/2) = (-1/2; 2)

e) (x-x1)/(x2-x1) = (y -y1)/(y2 -y1)

(x+3)/(2+3) = (y-1)/(3-1)

2(x+3) = 5(y-1)

2x +6 -5y +5 = 0

2x -5y +11 = 0