Question

Va rog urgent va rog dau coruana

Answer 1

$\it \left.\begin{aligned}0^{10}=0\\ \\ 1^{35}=1\\ \\ 53^0=1\\ \\ 35^1=35\\ \\ 5^3=125\\ \\ 3^5=243\\ \\ 10^{10}<35^{10}\end{aligned}\right\} \Rightarrow 0^{10}<1^{35}=53^0<35^1<5^3<3^5<10^{10}<35^{10}$