Question

va rog urgent va rog mult​

Answer 1

$notam \: cu \: x \: prima \: pare \: a \: funiei \: si \: cu \: y \: a \: doua \: parte \\ \\ x + y = 3 \frac{5}{6} = \frac{3 \times 6 + 5}{6} = \frac{23}{6} \\ x = y + \frac{1}{2} \\ inlocuim \: in \: pria \: relatie \\ \\ y + \frac{1}{2} + y = \frac{23}{6} \\ 2y = \frac{23}{6} - \frac{1}{2} \\ 2y = \frac{23 - 3}{6} \\ 2y = \frac{20}{6} = > 12y = 20 = > y = \frac{20}{12} = \frac{5}{3} \\ \\ x = \frac{5}{3} + \frac{1}{2} \\ x = \frac{10 + 3}{6} = \frac{13}{6} \\ deci \: prima \: parte \: are \: \frac{13}{6} m \: si \: a \: doua \: are \: \frac{5}{3} m$