Question

Va rog va implor am nevoie urgent

Answer 1

$\it 1)\\ \\ a)\ 2005^0=1;\ \ 3^4=81;\ \ 1^{2005}=1;\ \ 3^3=27\\ \\ \\ b)\ \ 3^{101}:9^{50}=3^{101}:(3^2)^{50}=3^{101}:3^{100}=3^{101-100}=3^1=3\\ \\ \\ c)\ =\Big[(196-169):27-1\Big] \cdot2+1=(27:27-1)\cdot2+1=(1-1)\cdot2+1=1$